How to create API with Json as output

Hi,Friends

How to create a API in PHP which gives a json output

First of all json is very light and secured way of getting data from an API. we will make an API to output a json

Here is a simple example

File: index.php

<?php
 $url = 'http://localhost/jsonapi/json.php';//url for json
 
 include('connect.php');//db connnection
 
 $query = "SELECT * FROM category";

$result = mysql_query($query) or die("Query failed");
  
       while ($row = mysql_fetch_array($result)) {
          $record[]=array($row["id"],$row["categoryname"]);
     }
 //curl for secured transaction of data

   $ch=curl_init($url);
    $data_string = urlencode(json_encode($record));
    curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST");
    curl_setopt($ch, CURLOPT_POSTFIELDS, array("category"=>$data));


    $result = curl_exec($ch);
    curl_close($ch);

   // echo $result;
?>


File: json.php

<?php
$data = $_POST['category'];
$output_data = ( urldecode( $datastring));
print_r($output_data);
?>
Function mainly used is json_encode

Now just run these file and you will get a json output for your API

just simple as that!!!!!!!!

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